Question

4. A car accelerates from 6 m/sto 16 m/s in 10 sec. Calculate (a) the acceleration and (b) the distance covered by the car in that time.

Answer 1

Answer:

u = 6m/s

v = 16m/s

t = 10s.

a = v-u/t

a  = 16-6/10

= 10/10

a = 1m/s²

distance =?=s

We know that,

2as = v²-u²

2(1)(s) = (16)²-(6)²

2s = 256-36

2s = 22o

s = 110

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Answer 2

Explanation:

This is the answer

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