4. A car and a bicycle start off from Town X at 10 a.m. together. If the car is 9 km ahead
of the bicycle at 10.10 a.m., what is the difference in their speed?
(1) 30 km/h (2) 48 km/h (3) 54 km/h (4) 69 km/h ()
Answers
Step-by-step explanation:
let the distance traveled by the car be x and bicycle be x-9
time taken = final time - initial time
= 10:10-10:00
= 10 mins = 10/60= 1/6= 0.16
speed of car would be greater than the speed of bicycle ( because car is ahead of the bicycle)
difference in their speeds= speed of car- speed of bicycle
= (x/0.16) - (x-9/0.16) { speed= distance / time}
= x-x+9/ 0.16
= 9/0.16
= 900/16
= 56.25
sorry it is not one from the given options but this is the ans
please tell if it helped you
Answer:
option (3) is correct
Step-by-step explanation:
Let the distance by car = (x +9) km
Let the distance by bicycle = x km
The time which both stated their journey = 10:00am
Time at which they were compared= 10:10 am
Which means it took 10 mins = 1/6 hr
So,
Speed of car = x+9/1/6 km/hr = 6(x+9) km/hr
Speed of bicycle = x/1/6 km/hr = 6x km/hr
Difference in their speeds = 6(x+9)-6x = 6x+54-6x = 54 km/hr
Hence, option (3) is correct
Pls mark this answer as the Brainliest answer!!!