Question

4. A car initially at rest starts moving with a
constant acceleration of 0.5 ms and travels a
distance of 25 m. Find : (i) its final velocity and
(ii) the time taken.
Given, initial velocity u=
0.
acceleration a = 05 m
distance travelled S - 25 m.
(i) From equation of motion v = + 2as
V2 = (0)2+2 x 0.5 x 25
= 25
or Final velocity v = 25 = 5 ms!
(ii) From equation of motion v = u + at
50+ 0.5 xt or 0.575
S
.. Time taken!
- 10 s.
05
or​

Answer 1

Answer:

Time taken is 5sec

Hope it helps you