4. A car is moving with speed of 20 m/s. After applying the brakes, if the maximum
deceleration produced is 10m/s2,then find the distance covered by the car before coming to rest.
Answers
Answered by
3
Explanation:
initial velocity (u) = 20 m/s
final velocity (v) = 0 m/s ( finally the car comes to rest )
Acceleration = -10 m/s ² ( retardation)
2as = v² - u²
2 × ( - 10 m/s²) ×s = (0m/s)² - ( 20 m/s ) ²
-20 s = - 400
s = - 400/ -20
s = 20 m
hope this will help you
Similar questions
Math,
3 months ago
Math,
3 months ago
Chemistry,
3 months ago
India Languages,
6 months ago
Hindi,
6 months ago
Social Sciences,
11 months ago
Science,
11 months ago