Question

4. A coin is tossed thrice. What is the probability of getting two consecutive tails?​

Answer 1

Answer:

Sample space = {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}

n(S) = 8

Let A be the event of getting consecutive traits

A = {HTT, TTH, TTT}

n(A) = 3

P(A) = n(A)/n(S) = 3/8

Answer 2

Answer:

A coin is tossed thrice. The sample space is.

S={HHH, HTH, THH, TTH, HTT, THT, HHT, TTT}.

n(S) =8

A={TTH, HTT, TTT}

n(A) =3

Therefore, P(A) =n(A) /n(S) =3/8.

Step-by-step explanation: