Question

4. A con cave lens has a focal length of 10cm. An object 2.5cm high is placed
30cm from the lens. Determine the position, size and nature of the image. Al
draw the ray diagram for the same.​

Answer 1

Answer:

s size and the position of the images 0.625 and -7. 5 CM respectively

focal length of the concave lens is negative so f equal to minus 10 cm

object distance from the lens is u equal to minus 30 cm

1f=1/v-1/u where is focal lens means the image distance from the lens and u is the object distance from the lens

by putting the values in the above formula we get

v=-7.5cm

and we know that magnification is equals to height of the image to the height of the object

so,m= v/u= H1/H0

by putting the value we get

H1/2.5=-7.5/-30

H1=0.625