Question

4. (a) Convert the given temperatures to °C.
(1) 150 °F (ii) 48 °F
(b) Convert the given temperatures to F.
(1) 150 °C (ii) 32 °C




plz answer the question step by step​

Answer 1

Answer:

1 - °F= 9/5 ×°C +32

then...

(150×5)/9-32 = °C

then... 750/9 -32 = 83.33 -32= 50.7°C

2-48°F = 1.8×C +32

then..

48/1.8 -32 = 26.6 -32 = -5.4 °C

3-°F = 9/5 °C +32 = 9/5 ×150 +32 = 30×9 +32 = 270 +32 = 302 ans....

4 - ° F= 9/5 ×°C +32 = 9/5 ×32 +32 = 288/5 +32 = 57.6 +32 = 89.6 °F

hope it helps you....

Answer 2

Answer:

Explanation:

1) Celsius if converted to Fahrenheit

     ( °C * 9/5 )+32 =°F

therefore, 150°C=(150*9/5)+32=270+32=302°F

ii)32°c=(32+9/5)+32=57.6+32=89.6°F

now just take every thing except °c to the (rhs) , to the side and change their sign  ie,  

                    °c=(°F-32)÷9/5 = (°F-32)*5/9                     (reciprocal of 9/5=5/9)

therefore 150°F=(150-32)*5/9=118*5/9=66°c(approx)

48°F=(48-32)*5/9=30°(approx)