Physics, asked by dristlamichhane, 5 months ago

4.
A copper kettle of mass 1 kg contains 0.9 kg of water at 15°C. It takes 12 minutes to rise the
temperature to 95°C. If the electric energy is supplied at 220V, calculate the electric current,
assuming 10% of heat is wasted. Given specific heat of copper = 420 J kg-K-1 and specific heat of
water = 4200 J kg-1 K-1.​

Answers

Answered by hellobaby40
0

Sabhi bachche neeche di gayi list mein apne apne ROLL NO. ke samne apna NAME aur working Mobile no. Likhein..its URGENTLY REQUIRED !

1. Ankit kumar 8810547022

2.

3.Shikher Panwar, Phone No.8130485273

4.

5.

6.

7.

8.

9.

10.kunal kumar 7678589293

11.

12.

13.

14.

15.

16.

17.

18.

19.

20.Ankit yadav 7289077535

21.

22.

23.prince kumar 9999150823

24. Karan 7291838765

25. vishal gupta

Roll no-25

9310651354

26.

27.

28.Sunny=9310532489

29.Aman Kumar

Phone no:9625319856

30.Md Imtiyaz Alam, phone no. 9315243268

31.

32.

33.

34.

35.

36.Sumit kumar, 9868388456

37.

38.

39.

40.

41.

42.

43. Name AYushman mobile no 9810616787

44.

45.

46.

47.

48.

49.

50.

51.

52.akash phone no-8287613713

53.Akash:-8587043228, 8826867450

54.

55.

56.HITESH KUMAR PATRA, NO=8447095558

57.

58.

59.

60.

61.

62.

Answered by pallavi8221
0

Given the power rating of the electrical kettle

P=2.1kW

If time taken to raise the temperature of 1 kg of water from

20∘

→100∘C

is t sec, then the electrical energy required for this will be

=pt

=2.1t kJ

Again the heat energy reqired to raise the temperature of 1 kg of water from 20∘

→100∘C is1×4200×(100−20)J

=336KJ

So 2.1t=336

⇒t=3362.1

=160s

= 2 min 40 sec

Similar questions