Question

4. A cricket ball of mass 70 g moving with a velocity of 0.5 m/s is stopped by a
player in 0.5 s. What is the force applied by the player to stop the ball ?​

Answer 1

Given :

• m = 70g
• g = 0.070 kg
• u = 0.5 m/s
• v = 0
• t = 0.5s

Find :

• The force applied by the player to stop the ball ?

Solution :

❁ We Know - :

• Force, f = m (v - u/ t)

→ F = 0.070 (0 - 0.5 / 0.5)

→ F = - 0.07 N

• Hence, The force applied by the player to stop the ball is - 0.07 N.

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