Question

4. A driver of a car A travelling at a uniform speed of
54 km/h for 10 s applies the brakes and decelerates
uniformly. The car stops in 5 s. Driver of car B
going at 36 km/h for 10 s applies the brakes slowly
and stops after 10 seconds. Plot the speed-time
graph of both cars and find out which of the two
cars travelled farther after the brakes were
applied ?​

Answer 1

Step-by-step explanation:

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Answer 2

(A)   :         Initial speed of the car A      u=52  kmh−1=52×185=14.44  ms−1

               The car stops in 5 seconds        i.e     v=0  at  t=5

(A)   :         Initial speed of the car A      u=3  kmh−1=3×185=0.83  ms−1

               The car stops in 10 seconds        i.e     v=0  at  t=10

With the help of these initial and final points for both the cases,  we can plot the graph of speed vs time.

Area under the speed-time graph gives the distance covered.

∴   Distance covered by car A       xA=21×14.44×5=36.1 m

∴   Distance covered by car A       xB=21×0.83×10=4.15 m

Thus car A travels more distance than B.