Question

4. A farmer ploughed 2/7 of his farm in the first week, 3/5 of the remaining in the second week and the rest during the third week. What fraction did he plough in the third week? *

Answer 1

Step-by-step explanation:

1st week + 2nd week + 3rd week = 1

2/7 + 3/5 + 3rd week = 1

3rd weel = 1 - 31/35

= 4/35

Answer 2

Answer:

$the \: fraction \: is \: \frac{4}{35}.$

Step-by-step explanation:

Farm ploughed in 1st week= 2/7

farm ploughed in 2nd week=3/5.

farm ploughed in 3rd week= 1- farm ploughed in 1st and 2nd week.

therefore,

$1 - \frac{2}{7} + \frac{3}{5}$

Now, by taking LCM of 5&7 i.e 35

$= > \frac{35(1) - 5(2) + 7(3)}{35} \\ = > \frac{35 - 10 + 21}{35} \\ = > \frac{4}{35}$

Hence,the farmer ploughed 4/35 of land in 3rd week.

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