Question

4.A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. Five seconds later, the fish is swimming in the same direction at a speed of 2.5 m/s. Calculate the fish’s acceleration?

Answer 1

Explanation:

Question:

A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark appear behind it. Five seconds later, the fish is swimming in the same direction at a speed of 2.5 m/s. Calculate the fish’s acceleration?

Aswer:

Given:

v₀ = 0.5 m/s

v = 2.5 m/s

t = 5 s

Find: a

v = at + v₀

2.5 m/s

= a (5 s) + 0.5 m/s

a = 0.4 m/s²

Answer 2

Answer:

The acceleration of the fish is 0.4m/s².

Explanation:

We will use the first equation of motion to solve the question. i.e.

$v=u+at$

$a=\frac{v-u}{t}$      (1)

Where,

a=acceleration

v=final speed

u=initial speed

t=time

As per the question,

The constant initial speed with which the fish is moving(u)=0.5 m/s

The final velocity of the fish when the shark is behind it(v)=2.5 m/s

Time(t)=5 sceonds

By substituting these values in equation (1) we get;

$a=\frac{2.5-0.5}{5}=\frac{2}{5}=0.4m/s^2$

Hence, the fish’s acceleration is 0.4m/s².