Question

4. A flooring tile has the shape of a parallelogram whose base is 24 cm and the
corresponding height is 10 cm. How many such tiles are required to cover a floor of
area 1080 m²? (If required you can split the tiles in whatever way you want to fill up
the corners).​

Answer 1

Step-by-step explanation:

Given,

l=24cm (of a tile. b=10cm (of a tile )

Area of a tile (in parallelogram shape) =l×bcm^2

=24×10

=240cm^2

Total floor area =1080m

2

10000cm

2

= 1m

2

Required number of tiles to cover the floor area =

1080×10000/240

=45000

Answer 2

Given :-

A flooring tile has the shape of a parallelogram.

Base of the flooring tile = 24 cm

Height of the flooring tile = 10 cm

Area of the floor = 1080 m²

To Find :-

Area of flooring tile.

Number of tiles required to cover the floor.

Analysis :-

Find the area of the flooring tile by it's respective formula in substituting the given values.

Divide the area of the floor given by the area of each tiles in order to get the number of tiles required.

Solution :-

We know that,

• b = Base
• h = Height
• a = Area

By the formula,

$\underline{\boxed{\sf Area \ of \ parallelogram=Base \times Height}}$

Given that,

Base (b) = 24 cm

Height (h) = 10 cm

Substituting their values,

Area = 24 × 10

Area = 240 cm²

Since the area is in centimeters, we have to convert it to meters.

By converting,

1 cm = 0.01 m

240 cm = 0.024 m

Next,

Number of tiles required to cover the floor = Area of floor ÷ Area of one tile

Given that,

Area of each tile = 0.024 m²

Area of the floor = 1080 m²

Substituting their values,

Number of tiles required to cover the floor = 1080 ÷ 0.024

Number of tiles = 45000

Therefore, 45000 tiles are required to cover the floor.