Question

4. A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2? [If required you can split the tiles in whatever way you want to fill up the corners]
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Answer 1

AnSwEr:

45,000 tiles.

• Step-by-step explanation:

To find,

• No.of tiles required to cover the floor

$=\frac{area\ of\ floor}{area\ of\ 1\ tile}$

• base=24 cm
• height=10 cm

$=240\ cm^2$

$No.of tiles=\frac{area\ of\ floor}{area\ of\ each\ tile}$

$=\frac{1080\ m^2}{240\ m^2}$

$1080\times100000\div240\ cm^2=$

= 45,000 tiles.

Answer 2

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Base of flooring tile = 24 cm

⇒ 0.24 m

height of a flooring tile = 10 cm

⇒0.10 m [1cm = 1/100 m]

Now, Area of flooring tile= Base × Altitude

= 0.24 × 0.10 sq. m

= 0.024 m2

∴ Number of tiles required to cover the floor = Area of floor/area of one tile

= 1080/0.024

= 45000 tiles

Hence 45000 tiles are required to cover the floor.