Question

4. A force F= (5i+3j+2k)N is applied over a particle which
displaces it from its origin to the point i = (2i - j)m. The
work done on the particle in joule is
(a) +10
(b) +7
(c) -7
(d) +13​

Answer 1

Answer:

work done is

=(5i+3j+2k). (2i - j). J

=10-3=7. joule

Answer 2

Answer:

Work done= vector F . vector s (dot product)

= (5×2) + (3x-1) +(2×0)

= 10 - 3 +0

= +7 Joule

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