4) A force of 60 N act on a charge of 15 x 10-2C. Calculate value of
electric field intensity at that point.
(a) 400 N/C
(b) 40 N/C
(c) 900 N/C
(d) 90 N/C
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a)
Ob)
c)
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Answer:
E = F / Q
E = 400N/C
PLEASE MARK BRAINLIEST
Explanation:
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