4. a) How fast should a 1,150 kg car move to make a circular turn of radius 48m on a flat concrete road, if the coefficient of friction between the tires and the road is 0.56? Purpose is to avoid skidding.
b) How fast should a 1,150 kg car move to make a circular turn of radius 56 m on a banked road elevated at an angle of 12 degrees?
5. A satellite is in a circular orbit around the Earth at an altitude of h = 1, 250 km above the Earth's surface. The radius of the Earth is equal to R_=6.37x10m , the mass is 5.98x10²4 kg. A) Find the speed of the satellite, and B) Find the period, which is the time it takes to make one complete revolution. C) Find the centripetal acceleration. Consider a horizontal circle.
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The speed of the car should be v = 263.424 m/s
Explanation:
We are given that:
- Mass of car = 1150 Kg
- The radius of the road = 48 m
- Coefficient of friction between the tires and the road = 0.56
- To Find: Speed "v" = ?
Solution:
The formula is
μmg = mv^2 / r
v = √μgr
v = √0.56 x 9.8 x 48
v = 263.424 m/s
Thus the speed of the car should be v = 263.424 m/s
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