Question

4. A is twice as old as B. When 6 is subtracted from
B's age and 4 is added to A's age, A's age will be
four times B's age. How old are they?​

Answer 1

Answer:

Who is older, great it is A, so B is younger. Now substract 6 years from the present age of B. Now B becomes a child. Again add 4 years to the present age of A,then A becomes older than B.

Now. A+4 = 4 ( B-6 ), Now A is twice as old as B , that is. A = 2 B. therefore.

2 B +4 = 4B - 24. solving B = 14 years and A = 28.

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