Question

4. A is twice as old as B. When 6 is subtracted from
B's age and 4 is added to A's age, A's age will be
four times B's age. How old are they?
answer is.
A's age =28years
B's age=14years .
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Answer 1

Answer:

a is twice as old as b. when 6 is subtracted from b age and 4 is added to a sade as will be four times

Step-by-step explanation:

aAsa age

$= 28years \:$

Answer 2

A is twice as old as B. When 6 is subtracted from B and 4 is added to A, A's age will be 4 times B's age. How old are they?

STEP-BY-STEP EXPLANATION

Let B = B 's age. Then 2B = A 's age. These are their present ages.

When 6 is subtracted from B , the expression is B−6.

Four added to A is A + 4 =2B + 4.

So now A 's age is 4 times that of B . So solve this equation:

A+4=4(B−6)

2B+4=4(B−6)

2B+4=4B−24

4+24=4B−2B

28=2B,

$\frac{28}{2} = \: b$

So, B = 14 is B 's age.

It follows that A 's age is 2B = 12 * 4 = 28

Answers are 14 and 28

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