Question

4. A man borrows 6,000 at 5 percent CL per
annum. If he repays * 1.200 at the end of
each year, find the amount of the loan
outstanding at the beginning of the third
year.​

Answer 1

Answer:

Correct option is

A

4155

P=6000 per month , R=5%

After 1 year

Interest=

100

PRT

=

100

6000×5×1

=300

New principle will be 6000+300=6300 but Rs 1200 was repaid

⟹P

′

=6300−1200=5100

After 2 years

Interest=

100

P

′

RT

=

100

5100×5×1

=255

Principle for 3

rd

year =5100+255=5355 but again Rs 1200 was repaid

∴ Outstanding =5355−1200

=4155

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Answer 2

Answer:

Money outstanding starting of Third year = Rs.4155

Step-by-step explanation:

${\blue{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$

Principle amount = Rs.6000

Rate of interest =  5% compounded annually

${\blue{\bigstar}} \ {\underline{\green{\textsf{\textbf{Solution :-}}}}}$

Interest after 1 year = 6000 × 5 × 1100 = 60× 5 = Rs . 300

Total money owed after 1 year = 6000 + 300 = 6300 and  Rs. 1200 paid

Total money starting of second year = 6300 - 1200 = Rs.5100

Interest after 2 year = 5100 × 5 × 1100 = 51 × 5 = Rs . 255

money owned after 2 year = 5100 + 255 = 5355

Total money outstanding starting of Third year = 5355 - 1200 = Rs.4155

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