Question

4. A man can throw a ball to a maximum vertical distance of 200 metre;
then what would be the maximum horizontal distance upto which he
can throw the ball, assuming the ball to have same initial velocity.​

Answer 1

Hmax= U^2/2g

So, from here, U^2 = 4000

Now, for Rmax, theta = 45

So,

R = U^2 sin(2×theta)/g

400m