Question

4) A man has rupees x with him .He gave half to his wife ,1/3 to his son and rest of rupees 1500 to his daughter.Form an equation in x​

Answer 1

Answer:

Now, share of wife = Rs. 45,000

and share of son = Rs. 30,000

Answer 2

Answer:

the Salary of the man = Rs. 9000

Amount given to his wife = Rs. 9000/2 =  Rs. 4500

Amount given to his son = Rs. 9000/3 =  Rs. 3000

Step-by-step explanation:

Amount that the man had = Rs. x

Amount given to his wife = Rs. x/2

Amount given to his son = Rs. x/3

Balance left was given to daughter = Rs.1500

so we write an algebraic equation as follows ,

x - { (x/2) + (x/3) } = 1500

=> x - [ (3x+2x)/6 ] = 1500

=> x - [ 5x/6 ] = 1500

=> (6x-5x)/6 = 1500

=> x/6 = 1500

=> x = 1500*6

=> x = 9000

so,

the Salary of the man = Rs. 9000

Amount given to his wife = Rs. 9000/2 =  Rs. 4500

Amount given to his son = Rs. 9000/3 =  Rs. 3000