Math, asked by chandu9236, 11 months ago

4
A man's age is six times that of his son's age. In six years the father's age
be three times the son's age. The age of the father and the son an
respectively
(a) 24,4
(b) 18,3 (c)30,5 (d) 42,7​

Answers

Answered by onlineshailendra
1

Step-by-step explanation:

(C) 6 and 36

Let son age = x

The age of father six times the age of his son = 6x

Four years hence = 6x +4. Eq 1

The age of father will be four times the age of his son = 4( x+4) Eq 2

Eq 1= Eq 2

6x+4= 4(x+4) = 6x +4 = 4x + 16 = 6x+4-4x-16 =0

2x = 12

x =12/2=6. x=6

Substitute in 6x = 6(6)=36

Hence 6 and 36

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