4. A man walks 8 m towards east and then 6 m towards north. His magnitude of displacement which he covers
is
(A) 10 m
(B) 14 m
(C)2m
(D) zero
Answers
Explanation:
Given:-
A man walks 8 m towards the East and then 6 m towards the North.
To find:-
What is his magnitude of displacement which he covers the distance?
Solution:-
Covered distance by a man towards the East = 8m
Covered the distance by the man towards the North = 6m
Convert this data into a diagram we get a right angled triangle
In ∆ ABC ,
BC = 8 m
AB = 6 m
The shortest distance between the starting point and the final point.
So here the shortest distance between point AC is the line joining it.
By Pythagoras theorem,
In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides .
AC^2 = AB^2+BC^2
=> AC^2 = 6^2+8^2
=> AC^2 = 36+64
=> AC^2 = 100
=> AC= ±√100
=AC = ±10 m
Distance can not be negative
AC = 10 m
Answer:-
The total displacement which he covered the distance is 10 m
Option A
Used formulae:-
Pythagoras theorem:-
In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides .
