Question

4. A Mendelian experiment consisted of breeding tall pea plants
bearing violet flowers with short pea plants bearing white flowers.
Their F1 progeny was self bred to form 576 plants of F2 generation
Calculate the number of short pea plants bearing white flowers
out of 576 plants. (plz explain full) ​

Answer 1

Explanation:

HEY MATE ..

According to the law of dominance, a dihybrid cross between two pure-breeding varieties yields uniforms F 1generation of all dominant offspring. Since here F 1generation consists of short plants with violet flowers and tall plants with violet flowers in a 1:1 ratio; the dominant parent is not purebred. The absence of a dominant allele for flower color (violet) would make the phenotype of dominant parent tall with white flowers. The appearance of the recessive trait in F 1generation (dwarfism) confirms the presence of one recessive allele in the dominant parent and makes it heterozygous for plant height (Tt). Since all F 1generation has a violet flower, the dominant parent is homozygous for flower color. If the dominant parent was double heterozygous (TtWw), the F 1 generation would exhibit recessive traits of both plant height and flower color. But all F

1generation exhibits violet flowers which confirm that the dominant parent is homozygous for flower color.

TtWW is the right answer