Question

(4)
A metal cuboid of measures 16 cm x 11 cm x 10 cm was melted
to make coins. How many coins were made, if the thickness and
diameter of each coin was 2 mm and 2 cm respectively ?
cylinder 1cm = 10mm​

Answer 1

•Volume of metal cuboid is = 16 cm ×11 cm × 10 cm =1760 cm^3

Now,the thickness of coin is = 2 mm= 0.2 cm

The thickness(h) of coin is 0.2 cm

Radius of coin(r) = diameter /2 cm =2/2 cm =1 cm

As the coin has cylindrical shape .

So, volume of coin is = π(r^2)h= 0.628 cm^3

(as π =22/7= 3.14)

so,the number of coins = volume of metal cuboid/volume of one coin= 1760/0.628 =2802.54

So, the number of coins were made is 2802.

Answer 2

Step-by-step explanation:

Given A metal cuboid of measures 16 cm x 11 cm x 10 cm was melted  to make coins. How many coins were made, if the thickness and  diameter of each coin was 2 mm and 2 cm respectively ? 1 cm = 10 mm

• Given dimension of the metal cuboid = 16 cm x 11 cm x 10 cm  
• Thickness of the coin = 2mm = 0.1 x 2 = 0.2 cm
• Diameter of coin = 2 cm, so radius will be r = d/2 = 2/2 = 1 cm
• We know that area of a circle = π r^2
•                                               = 22/7 x 1 x 1
•                                               = 22/7
• Also total area of one coin will be 22/7 x 0.2 (thickness)
•                                                   = 4.4 / 7
• Now total number of coins will be total area of metal cuboid / total area of one coin
•                                                    = 16 x 11 x 10 x 7 / 4.4
•                                                    = 12,320 / 4.4
•                                                   = 2800 coins

Reference link will be

https://brainly.in/question/15974783