4. A metal sheet, 27 cm long, 8 cm. broad and 1
cm thick, is melted into a cube. The difference
between the surface areas of two solids is
A. 284 cm2 B. 286 cm2
C. 296 cm D. 300 cm
Answers
Answered by
6
Volume of sheet = volume of cube
First we will calculate volume of metal sheet =l X b x h
= 27 x8 x1=216cm^3
So volume of the cube is also 216 cm^3
216=a^3
3√216
= 6
So surface area of sheet = 2(lb+bh+hl)
=2(27x8+8x1+1x27)
=502cm^2
And surface area of cube
=6a^2
=6 x6^2=216cm^2
Difference between surface area = 502-216=286cm^2
surajkj45:
thanks
Answered by
2
here is your answer mate....
surface area of cuboid will be.. 2(lb+bh+hl) = 2(27×8+8×1+1×27)
2(216+8+27)=2(251)=502 cm^2
although the cube is made from same cuboid volume of both will be same... hence,...
let side of cube be a
l×b×h = a^3
27×8×1=a^3
a= 3√216= 2×3=6
therefore.... surface area of cube= 6a^2 6×6^2=36×6=216cm^2
therefore difference between them will be 502-216=286cm^2 ans....
hope this helps you.....
surface area of cuboid will be.. 2(lb+bh+hl) = 2(27×8+8×1+1×27)
2(216+8+27)=2(251)=502 cm^2
although the cube is made from same cuboid volume of both will be same... hence,...
let side of cube be a
l×b×h = a^3
27×8×1=a^3
a= 3√216= 2×3=6
therefore.... surface area of cube= 6a^2 6×6^2=36×6=216cm^2
therefore difference between them will be 502-216=286cm^2 ans....
hope this helps you.....
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