Question

4. A mixture of peas and guavas kept together in a basket can be separated by (a) sieving (b) handpicking (c) sedimentation (d) evaporation 3. The metho can be sepa 4. A method of a mixtu​

Answer 1

Explanation:

Let the length, breadth, and height of the cuboid be 5x,3x and 2x respectively.

We know that the volume of the cuboid is l×b×h.

It is given that the volume of the cuboid is 35.937 m

3

, therefore,

35.937=5x×3x×2x

⇒30x

3

=35.937

⇒x

3

=

30

35.937

=1.197

⇒x=

3

1.197

⇒x=1.06177

Therefore, the length l=5x=5×1.06177=5.309m, breadth b=3x=3.185m and height h=2x=2.124m

Now, the total surface area of cuboid is 2(lb+bh+hl), therefore, the total surface area with length 5.309 m, breadth 3.185 m and height 2.124 m is:

A=2[(5.309×3.185)+(3.185×2.124)+(2.124×5.309)]=69.9 m

2

Answer 2

Explanation:

(b) handpicking Guess this