Question

4. A motorboat starting from rest on a lake accelerates in a straigh
line at a constant rate of 3.0 m s-for 8.0 s. How far does the
boat travel during this time?​

Answer 1

Explanation:

Final velocity is 3 m/s

Initial velocity is 0 m/s (starting from rest)

time is 8 sec

distance (s) =?

a = v-u/t

a= 3-0/8

a = 3/8

S = ut +1/2 at^2

S= 0+ 1/2×3/8×8×8

S = 12 m

Answer 2

Answer:

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

• u = 0 [starting from rest]
• t = 8 sec
• a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.