Question

4. A motorboat starting from rest on a lake accelerates in a straigh
line at a constant rate of 3.0 m s-2 for 8.0 s. How far does the
boat travel during this time?
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Answer 1

Given

u=0m/s(since the boat starts from rest)

acceleration =3m/s^2

t=8 s

Now distance travelled by boat in the given time =ut+1/2at^2

=0m/s ×8s +1/2×3m/s^2 ×8s^2

=0+4×3m

=0+12m

=12m

Answer 2

Answer:

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.