Question

4. A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m s-2 for 8.0s.how far does the boat travel during this time?​

Answer 1

Q: FIND THE DISTANCE TRAVELLED DURING THIS TIME ?

A: THE DISTANCE IS 96m DURING THIS TIME.

EXPLANATION.

DATA.

Vi = 0ms^-1

a = 3ms^-2

t = 8s

S = ?

FORMULA. 2ND EQUATION OF MOTION.

S = Vit + 1÷2at^2

SOLUTION.

S = 0 × 8 + 1÷2 ×3 × 8 ^2

S = 0 + 1÷2 × 3 × 64

S = 1÷2 × 192

S = 96m.

HOPE YOU UNDERSTAND

AND HERE IS THE ATTACHMENT.

Answer 2

Answer:

➧ u ➾ 0 m/s

➧ u ➾ 0 m/s➧ a ➾ 30 m/s²

➧ u ➾ 0 m/s➧ a ➾ 30 m/s²➧ t ➾ 8 sec

➧ u ➾ 0 m/s➧ a ➾ 30 m/s²➧ t ➾ 8 sec❱S ➾ ut + ½ at²

➧ u ➾ 0 m/s➧ a ➾ 30 m/s²➧ t ➾ 8 sec❱S ➾ ut + ½ at²S ➾ 0 × 8 + ½ × 3 × (8)²

➧ u ➾ 0 m/s➧ a ➾ 30 m/s²➧ t ➾ 8 sec❱S ➾ ut + ½ at²S ➾ 0 × 8 + ½ × 3 × (8)²S ➾ ½ × 3 × 64 

➧ u ➾ 0 m/s➧ a ➾ 30 m/s²➧ t ➾ 8 sec❱S ➾ ut + ½ at²S ➾ 0 × 8 + ½ × 3 × (8)²S ➾ ½ × 3 × 64   ➾ 96 m ...✔

➧ u ➾ 0 m/s➧ a ➾ 30 m/s²➧ t ➾ 8 sec❱S ➾ ut + ½ at²S ➾ 0 × 8 + ½ × 3 × (8)²S ➾ ½ × 3 × 64   ➾ 96 m ...✔_________               Thanks...✊