Question

4. A motorcycle traveling at 25 m/s accelerates at a rate of 7.0 m/s2 for 6.0 seconds. What is the final velocity of the motorcycle?

Answer 1

Final Answer: 67m/s

Initial velocity, u=25m/s
Final velocity, v = ?
acceleration, a= 7m/s^2
Now, Newton's first equation of motion ,
v = u+ at
v = 25+ 7*6
= 25+42 = 67m/s

Answer 2

Answer:

Final velocity of the motorcycle is 67 m/s.

Explanation:

let, initial velocity be u

     final velocity be v

     acceleration be a

and time be t

here, u= 25 m/s

        a= 7 m/s^2

        t = 6 sec.

we know, v= u+ at

                v= 25 + 7*6

                v= 67 m/s.

therefore, final velocity of the motorcycle is 67 m/s.