Question

4. A number consists of two digits whose sum is
5. When the digits are reversed, the number
becomes greater by 9. Find the number​

Answer 1

when the digits are reversed the number becomes greater by 9 find the number.

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Answer 2

hope this helps u

Let the digits in the tens be x and ones place be y.

Hence the number is 10x+y

By reversing 10y+x

Sum of digit =5

⇒x+y=5⟶(i)

Also that when 9 is added to the number the digits get interchanged.

∴(10x+y)+9=(10y+x)

10x+y+9=10y+x=0

9x−9y=−9

x−y=−1⟶(ii)

Adding (i) &(ii) we get ,  

⇒x+y=5

⇒x−y=−1

⇒2x=4

⇒x=2

Put x=2 in x+y=5  

∴2+y=5

⇒y=3

Hence the number is 23.