Question

4. A number exceeds 8105 by 1155. What is that number?
5. The sum of three "numbers is 7789. If two of them are 4131 and 2271, find
the third number.
6. Subtract the difference of 5626 and 3377 from 9630.​

Answer 1

Answer:

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Answer 2

$4 ) Let \: a\: number \: exceeds\: 8105\: by\\ 1155\: be \: \pink {x}$

$\implies \pink {x} = 8105 + 1155 \\= 9260$

$\red { Required \: number } \green { = 9260 }$

$5. Let \: x , y \: and \: z \: are \: three \\ numbers$

$Given \: x = 4131, \: y = 2271 \: \red { z = ? }$

/* According to the problem given */

$Sum \: of \: three \: numbers = 7789$

$\implies 4131 + 2271 \pink { + z } = 7789$

$\implies 6402 \pink { + z } = 7789$

$\implies \pink { z } = 7789 - 6402$

$\implies \pink { z } \green {= 1387}$

Therefore.,

$\red{ Third \: number } \green {= 1387}$

$6. \red {Subtract\: the \:difference \:of \: 5626}\\\red { and\: 3377 \:from \:9630}$

$\red{ Required \: number } \\= 9630 - ( 5626 - 3377 ) \\= 9630 - 2249 \\= 7381$

Therefore.,

$\red{ Required \: number } \green {= 7381}$

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