4. A paper bag is 16 cm long, 5 cm wide and 20 cm tall. Inside the bag is a box that is 8cm long, 3 cm wide and 10 cm tall. How much space is left in the bag?
5. A big locker is above a small locker. They are both 0.5 m wide and 0.6 m deep. The big locker is 1.2 m tall and the small locker is half of the height of the big locker. What is the total volume of one big locker and one small locker?
Answers
Answer:
let area of bag= lbh
=16×5×20
=1600cm²
let area of box =lbh
=8×3×10
=240cm²
space left in the bag=1600_240
=1360cm²
Answer:
4) The space left in the bag = 1360 cm³
5) Total volume of the big locker and small locker = 0.54 m³
Step-by-step explanation:
4)
Given data
A paper bag length = 16 cm
width = 20 cm
height = 5 cm
dimensions of box which is inside the bag
length = 8 cm
width = 3 cm
height = 10 cm
⇒ the space left in the bag = volume of bag - volume of the box
⇒ volume of bag = 16 ×20 ×5 = 1600 cm³
⇒ volume of the box = 8 ×3 ×10 = 240 cm³
⇒ the space left in the bag = 1600 - 240 = 1360 cm³
5)
Given data
A big locker is above a small locker
both are 0.5 m wide and 0.6 m deep
big locker height = 1.2 m
small locker height = half of the big locker
= 1.2/2 = 0.6 m
⇒ dimensions of the lockers
Big locker ⇒ width = 0.5 m
deep = 0.6 m
height = 1.2 m
⇒ volume of the big locker = (0.5) (0.6)(1.2) = 0.36 m³
small locker ⇒ width = 0.5 m
deep = 0.6 m
height = 0.6 m
⇒ volume of small locker = (0.5)(0.6)(0.6) = 0.18 m³
total volume of the big locker and small locker
= volume of big locker + volume of small locker
= 0.36 m³ + 0.18 m³ = 0.54 m³