Question

4. A parallel beam of light of wavelength 6 x 10^-5 cm
falls normally on a straight slit of width 0.2 mm.
Find the total angular width of the central diffraction
maximum and also its linear width as observed on a
screen placed 2 metre away.
Ans. 6 x 10 radian, 1.2 cm.​

Answer 1

Answer:

Explanation:- Wavelength = 6 X 10^-5 cm.=6 X 10^-7 m.      

width of slit d=0.2mm. =2x10^-4m.

angular width= λ/d

                      =6x10^-7/2x10^-4

                     =3x10^-3 rad.

Linear width-

                       β=λD/d    Where D is the distance of the screen.

                    so,β=3x10^-3 x 2

                           =6x10^-3 m.