Question

4. A particle executes SHM such that the
maximum velocity during the oscillation is
numerically equal to half the maximum
acceleration, what is the time period ?​

Answer 1

Answer:

Hey buddy,

● Answer-

T = 3.142 s

● Solution-

# Given-

vmax = 1/2 amax

# Solution-

We know that, for a particle in S.H.M.

vmax = Aω

amax = Aω^2

But we have,

vmax = 1/2 amax

Aω = 1/2 Aω^2

ω = 2 rad/s

Time period is given by

T = 2π/ω

T = 2π/2

T = π

T = 3.142 s

Hope that is useful...