Physics, asked by anku210, 10 months ago

4. A particle moves along a curve y = x2 with constant
speed of 10 m/s. When the particle is at origin, then
the radius of curvature of path is
(1) 0.5 m
(2) 2.0 m
(3) 1.5 m
(4) 1.0 m​

Answers

Answered by Anonymous
1

Answer:

i think the answer is 0.5m

Answered by azizalasha
1

Answer:

solved

Explanation:

curvature R = { 1 + y'²}^3/2 ÷ y'' = { 1 + 4x²}^3/2 ÷ 2

at origin , x = 0

R = 1/2 = 0.5 m

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