Question

4. A particle ptart from origin at t =0 with a velocity 5.0i m/s and moves along xy plane under the action of a force which produces a constant acceleration of 3.0i +2.0j m/s^2
(a) What is y coordinate of partical at the instant its X coordinate
is 84 m ?
(6) What is speed of particle at this time?​

Answer 1

U

x

=5

i

^

(m/s)

U

y

=0(m/s)

a

x

=3

i

^

(m/s

2

)

a

y

=2

j

^

(m/s

2

)

(a)

S

x

=

U

x

t+

2

1

a

x

t

2

84

i

^

=5t

i

^

+

2

1

×3×t

2

i

^

∴3t

2

+10t=168

3t

2

+10t−168=0

3t

2

+28t−18t−168=0

t(3t+28)−6(3t

2

+28)=0

(t−6)(3t

2

+28)=0

∵ time can't be negative.

∴t=6

At t=6,

S

x

=84

i

^

(m)

∴

S

y

=0+

2

1

a

y

t

2

j

^

=

2

1

×2×36

j

^

S

y

=36

j

^

∴Y− coordinate at (t−6)⇒36m

(b)

V

x

=

U

x

+

a

x

t

5+3×6

=23i(m/s)

V

y

=0+2×6

j

^

=12

j

^

(m/s)

∣V∣=

23

2

+12

2

25.94m/s$

∣V∣≈26m/s

Where ∣V∣= Speed of particle at t=6)

MARK me as brainlist...

Xd...