Question

4. A particle starts from rest and moves with a uniform acceleration of 5m/s2 for
and then it moves with a constant velocity for4 s. Later it slows down and con
rest in 5 s. Draw the velocity-time graph for the motion of the body and answ
the following questions :
(a) What is the maximum velocity attained by the body?
(b) What was the distance travelled when the body was moving with constant
velocity?​

Answer 1

Answer:

Explanation:u=0m/s

v=?

t=5sec

acce.=5m/s^2

v=u+at

o+5×5

25m/s

2.S=ut+1/2at^2

=0×5+1/2×5×5^2

= 0+1/2×125

= 62.5

3.the body is constant so there is no acce.

Now s=ut+1/2at^2

s=25×4+1/2×0×4^2

100+0

100m

4.retardation=u=25m/s,v=0m/s,t=5s

=0-25/5

=-5m/s^2

5.distance travel by retarding

v^2-u^2=2as

0^2-25^2=2×-5×s

0-625=-10s

-625=-10s

-625/-10=s

62.5m=s

6.total d travelled=

area of triangle +area of rectangle+are area of triangle

1/2×b×h+b×h+1/2×b×h

1/2×125×100+1/2×125

=225m