Question

4. A particle starts from rest. Its acceleration at time t = 0 is 5 ms which varies with time as shown in the
figure. The maximum speed of the particle will be
(A) 7.5 ms
-5 m/
(B) 15 ms
(C) 30 ms
(D) 37.5 ms​

Answer 1

Answer:

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Answer 2

Answer:

vf^2=vi^2+2as

Vf^2=0+2(5)(6)

Vf^2=0+60

Vf^2=60

√vf^2=√60

Vf= 7.75

Or

Vf=vi+gt

Vf=0+5(0)

Vf=0

Or

V=√2gh

V=√2(10)(6)

V=√120

V=11