Question

4.
A pendulum makes 40 oscillations in 4 second. Find its time period and frequency.​

Answer 1

Answer:

No of oscillations = 40

Time = 4 sec

Frequency = no of oscillations ÷ time

= 40 ÷ 4

=10 sec

Time period = 1/frequency

=1/10

=0.1 sec

Answer 2

The time period and frequency of the pendulum is 10 Hz and 0.1 second.

Explanation:

Given that,

Number of oscillations, n = 40

Time, t = 4 s

We need to find the time period and the frequency of the pendulum. The total number of oscillations per unit time is called frequency. It is given by :

$f=\dfrac{n}{t}$

$f=\dfrac{40}{4\ s}$

f = 10 Hz

The reciprocal of frequency is called time period of the pendulum. The time period is given by :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{10\ Hz}$

T = 0.1 second

So, the time period and frequency of the pendulum is 10 Hz and 0.1 second. Hence, this is the required solution.

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