Math, asked by ayushrajsoni55, 4 months ago

4- A piggy bank contains hundred 50 p coins, fifty Rs 1 coins, twenty Rs 2 coins
and ten Rs. 5 coins. If it is equally likely that one of coins will fall out when
the bank is turned upside down. What is the probability that the coin - 4
a. Will be a 50 p coin?
b. Will not be Rs 5 coin?​

Answers

Answered by Anonymous
0

Answer:

Total no. of coins in the piggy is 180

Solution(i):

No. of 50p coins in piggy is 100

Let E be the event of drawing a coin from piggy

We know that, Probability P(E) =  

(Total no.of possible outcomes)

(No.of favorable outcomes)

​  

=  

180

100

​  

=  

9

5

​  

 

Therefore,Probability that a 50p coin wins =  

9

5

​  

 

Solution(ii):

No. of coins with value >Rs. 1  in piggy is 30

Let E be the event of drawing a coin from piggy

We know that, Probability P(E) =  

(Total no.of possible outcomes)

(No.of favorable outcomes)

​  

=  

180

30

​  

=  

6

1

​  

 

Therefore,Probability that a coin with value >Rs.1  falls =  

6

1

​  

 

Solution(iii):

No. of coins with value <Rs 5  in piggy is 170

Let E be the event of drawing a coin from piggy

We know that, Probability P(E) =  

(Total no.of possible outcomes)

(No.of favorable outcomes)

​  

=  

180

170

​  

=  

18

17

​  

 

Therefore,Probability that a coin with value  <Rs.5  falls =  

18

17

​  

 

Solution(iv):

No. of Rs. 1  and Rs. 2  coins in piggy is 70

Let E be the event of drawing a coin from piggy

We know that, Probability P(E) =  

(Total no.of possible outcomes)

(No.of favorable outcomes)

​  

=  

180

70

​  

=  

18

7

​  

 

Therefore,Probability that a Rs. 1  and Rs. 2  coin falls =  

18

7

Step-by-step explanation:

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