Question

4. A player catches a ball of mass 150 g, travelling with a speed of 15 m/s. He pulls back
his hand through a distance of 0.3 metres. Find:
retardation of ball
(ii) momentum transferred to the player's hand
(w time taken by the ball to stop
(iv) force exerted by the ball on the player's hand.
loration of m/2
100 000​

Answer 1

Answer:

M=150g

v=20m/s

t=0.1s

a=(v−u)/t

=(20)/0.1

=200m

f=ma

=150×200

=30000/1000

=30N Ans.