Question

4. A positive number is 7 times another number. If 15 is added to both the numbers,
then one of the new number becomes 5/2 times the other new number. What are the numbers?​

Answer 1

Step-by-step explanation:

Let the number be x

Then the other number = 7x

According to the condition ,

x+15= 2/5(7x+15)

2(x+15)= 7+5x+5×15+2x+30=7+5x+7+75

On simplification we get,

2x− 7=5

x=75−30

7

14−5

x=45

7×9=45

x=45× 9×7

We get ,

x=35

Hence ,

One number =35

Other number =7/35

=5

Therefore , the numbers are 35 and 5

Answer 2

Step-by-step explanation:

Let another number be x.

Then positive number = 5x

According to the question, 5x+21=2\left(x+21\right)5x+21=2(x+21)

\Rightarrow5x+21=2x+42⇒5x+21=2x+42

\Rightarrow5x-2x=42-21⇒5x−2x=42−21

\Rightarrow3x=21⇒3x=21

\Rightarrow x=\frac{21}{3}=7⇒x=

3

21

=7

Hence another number = 7 and positive number = 7 x 5 = 35.