4. A pump is used to lift 300 kg of water from a depth of 50 m in 10 s. Calculate
a. the work done by the pump.
b. the power at which the pump works.
[Ans. a. W = 147000 J b. P = 14700 W ]
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Answers
(a) Work done :-
As we know that ,
• Work = mgh
→ Work = 300 × 10 × 50
→ Work = 150000 J or 150 kJ
Hence , work done = 15 × 10⁴ J
(b) Power :-
As we know that ,
• Power = Work/time
Simplifying ,
• Power = mgh/t
From the above solution , already we got , work = 150000 J . So ,
=> Power = 150000/10
=> Power = 15000 W or 15 kW
Hence , power = 15kW
➦ This question says that there is a pump and it is used to lift 300 kg of water from a depth of 50 m in 10 seconds. We have to calculate the following terms –
a. The work done by the pump.
b. The power at which the pump works.
➦ A pump is used to lift 300 kg of water
➦ It lift water from depth of 50 metres
➦ And it lift water in 10 seconds
➦ The work done by the pump.
➦ The power at which the pump works.
➦ The work done by the pump = 150000 Joules or 15 × 10⁴ Joules.
➦ The power at which the pump works = 15000 Watts
➦ Formula to find work done
➦ Formula to find power
➦ Work done => mgh
➦ Formula to find power => Work / Time
➦ m denotes mass
➦ g denotes acceleration due to gravity
➦ h denotes height
~ Finding work done
➦ Work done = mgh
➦ Work done = 300 × 10 × 50
➦ Work done = 3000 × 50
➦ Work done = 150000 J or 150 KJ too
- Therefore, work doned = 15 × 10⁴ Joules or 150000 Joules
~ Finding power
➦ Power = Work / Time
➦ Power = 150000 / 10
➦Power = 15000 Watts or 15 KW too
- Henceforth, power = 15000 Watts or 15 KW