Question

4. A rectangle has a fixed length, but varying breadth. The value of its area with respect to its breadth is given. Find the area of a rectangle with breadth 5 cm. Area (cm) 121 Breadth (cm) 11
Area(cm) ? Breadth(cm) 5​

Answer 1

$\Huge \orange{\underbrace \orange{\overbrace \pink {\fcolorbox{darkblue}{aqua} { Answer }}}} \dashrightarrow$

$\huge{Question} \dashrightarrow$

rectangle has a fixed length, but varying breadth. The value of its area with respect to its breadth is given. Find the area of a rectangle with breadth 5 cm. Area (cm) 121 Breadth (cm) 11

Area(cm) ? Breadth(cm) 5

$\huge \ To \: find \: :-$

Area of rectangle whose breadth is 5cm

$\huge solution \dashrightarrow$

Area of rectangle = length × breadth

Area = length × 5

so, first we have to find the value of length by given problem

$area \: of \: rectangle \: = l \times b \: \\ 121 = l \times 11 \\ l = \frac{121}{11} \\ \large\boxed{l = 11}$

Now we have found that length is 11 cm

Now we can find the area of rectangle with breadth 5 cm

$area \: of \: rectangle \: = l \times b \\ area = 11 \times 55 \\ area \: of \: rectangle : \\ \\ \huge\fbox \red{= 55cm}$

Answer 2

Answer:

⇢

\huge{Question} \dashrightarrowQuestion⇢

rectangle has a fixed length, but varying breadth. The value of its area with respect to its breadth is given. Find the area of a rectangle with breadth 5 cm. Area (cm) 121 Breadth (cm) 11

Area(cm) ? Breadth(cm) 5

\huge \ To \: find \: :- Tofind:−

Area of rectangle whose breadth is 5cm

\huge solution \dashrightarrowsolution⇢

Area of rectangle = length × breadth

Area = length × 5

so, first we have to find the value of length by given problem

\begin{gathered}area \: of \: rectangle \: = l \times b \: \\ 121 = l \times 11 \\ l = \frac{121}{11} \\ \large\boxed{l = 11}\end{gathered}

areaofrectangle=l×b

121=l×11

l=

11

121

l=11

Now we have found that length is 11 cm

Now we can find the area of rectangle with breadth 5 cm

\begin{gathered}area \: of \: rectangle \: = l \times b \\ area = 11 \times 55 \\ area \: of \: rectangle : \\ \\ \huge\fbox \red{= 55cm}\end{gathered}

areaofrectangle=l×b

area=11×55

areaofrectangle:

= 55cm