Question

4. A rectangle has an area of 165 sq. cm. If its breadth is 11 cm, find its perimeter​

Answer 1

Answer:

L= 15

P= 52

Step-by-step explanation:

A=L×B

165=L×11

165÷11=L

15=L

P=2(L+B)

P=2(15+11)

P=2(26)

P=52

Answer 2

Given :

• Area of Rectangle is 165 cm².
• Breadth of Rectangle is 11cm.

To Find :

• Perimeter of Rectangle.

Solution :

Firstly we will find length of Rectangle :

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Rectangle=length\times{breadth}}$

Putting Values :

$\longmapsto\tt{165=l\times{11}}$

$\longmapsto\tt{\cancel\dfrac{165}{11}=l}$

$\longmapsto\tt\bf{l=15cm}$

So , The length of Rectangle is 15cm..

Now ,

$\longmapsto\tt{Length=15cm}$

$\longmapsto\tt{Breadth=11cm}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{2(15+11)}$

$\longmapsto\tt{2(26)}$

$\longmapsto\tt\bf{52cm}$

Therefore , Perimeter of Rectangle is 52cm...