Question

4. A rectangular piece of ground is 45 m long and 30 m wide. It has two roads each 1m
wide, running midway within it, one parallel to the length and the other parallel to the
breadth. Find the area of the roads. Also calculate the area of the remaining ground.​

Answer 1

Answer:

Area of the remaining ground is 1276 m².

Answer 2

Step-by-step explanation:

Solution :-

Length = 45 m

Breadth = 30 m

Area of whole piece of rectangular

land = L*B

- 45*30 = 1350 m?

So, area of the whole rectangular piece of land = 1350 m2 =

Now,

Length of the 1st road parallel to the length = 45 m =

Breadth of the 1st road parallel to the length = 1 m

Area of the 1st road = 45*1

= = 45 m2

Length of the 2nd road parallel to the

breadth = 30m

Breadth of the 2nd road parallel to the

breadth = 1 m

Area of the 2nd road = 30*1 =

= 30 m2

Area of the common part of 2 roads =

1*1

= 1 m2

Total area of 2 roads = Area of 1st road + Area of 2nd road - Area of common

part

- (45 + 30) - 1

» 75 - 1

= 74 m2

So, the area of the 2 roads is 74 m²

So, the area of the 2 roads is 74 m?

Now,

Area of the remaining ground = Area of the whole rectangular piece of land - Area of 2 roads

- 1350 - 74

- = 1276 m2

Area of the remaining ground is 1276 m²