Question

4- A resistor of 8 ohm is connected in parallel with the another resistor x the
resultant resistance of the combination is 4.8 ohm .What is the value of X

​

Answer 1

Answer:

3Ω

Explanation:

we know that to find the total resistance in parallel circuits, use this formula

$\frac{1}{R_{p} } = \frac{1}{R_{1} }+ \frac{1}{R_{2} }+ \frac{1}{R_{3} }$

Now it is given that

$R_{p}= 4.8\\ R_{1} = 8\\R_{2} = x$

$\frac{1}{4.8 } = \frac{1}{8 }+ \frac{1}{x }$

$\frac{1}{x} = \frac{1}{4.8} -\frac{1}{8} \\\\\frac{1}{x} = \frac{1}{3} \\x=3$